CoffeeScriptTips

Gists

This is a sample script for combining and mixing 2 objects. Each object is an array which included a dictionary type. When the key of the dictionary object is the same, the values are mixed.

This can be also used for Google Apps Script.

Input

var obj1 = [
    {"key1": ["value1a1", "value1a2"]},
    {"key1": ["value1aa1", "value1aa2"]},
    {"key2": ["value2a1", "value2a2"]},
    {"key3": ["value3a1", "value3a2"]},
];
var obj2 = [
    {"key1": ["value1b1", "value1b2"]},
    {"key3": ["value3b1", "value3b2"]},
    {"key3": ["value3bb1", "value3bb2"]},
    {"key4": ["value4b1", "value4b2"]},
];

Output

[
    {"key1": ["value1a1", "value1a2", "value1b1", "value1b2", "value1aa1", "value1aa2"]},
    {"key2": ["value2a1", "value2a2"]},
    {"key3": ["value3a1", "value3a2", "value3b1", "value3b2", "value3bb1", "value3bb2"]},
    {"key4": ["value4b1", "value4b2"]}
]

Sample script :

Javascript :

function mixture(obj1, obj2) {
    Array.prototype.push.apply(obj1, obj2);
    var temp = [];
    var res = [];
    obj1.forEach(function(e, i){
        temp[i] = !~temp.indexOf(Object.keys(e)[0]) ? Object.keys(e)[0] : false;
        if (temp[i]) {
            res.push(e);
        } else {
            res.forEach(function(f, j){
                if (Object.keys(f)[0] == Object.keys(e)[0]) {
                    Array.prototype.push.apply(res[j][Object.keys(f)[0]], e[Object.keys(e)[0]]);
                }
            });
        }
    });
    return res;
}

var obj1 = [
    {"key1": ["value1a1", "value1a2"]},
    {"key1": ["value1aa1", "value1aa2"]},
    {"key2": ["value2a1", "value2a2"]},
    {"key3": ["value3a1", "value3a2"]},
];
var obj2 = [
    {"key1": ["value1b1", "value1b2"]},
    {"key3": ["value3b1", "value3b2"]},
    {"key3": ["value3bb1", "value3bb2"]},
    {"key4": ["value4b1", "value4b2"]},
];
var res = mixture(obj1, obj2);
console.log(JSON.stringify(res))

CoffeeScript :

This is a sample script for coffeescript.

Gists

This sample script is for removing duplicated values in array using CoffeeScript.

ar = ["a", "b", "c", "a", "c"]
res = ar.filter (e, i, s) -> s.indexOf(e) is i
console.log res

>>> [ 'a', 'b', 'c' ]

The result which was compiled by CoffeeScript is as follows.

var ar, res;
ar = ["a", "b", "c", "a", "c"];
res = ar.filter(function(e, i, s) {
  return s.indexOf(e) === i;
});
console.log(res);

This sample flattens a nested array using CoffeeScript.

flatten = (array) ->
    array.reduce(((x, y) -> if Array.isArray(y) then x.concat(flatten(y)) else x.concat(y)), [])

console.log flatten [1, [2, 3, [4, 5]], 6, [7, [8, [9], 10] ,11 , 12], 13]

>>> [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13 ]